0=-7n^2+8n

Solution for 0=-7n^2+8n equation:

0=-7n^2+8n

We move all terms to the left:

0-(-7n^2+8n)=0

We add all the numbers together, and all the variables

-(-7n^2+8n)=0

We get rid of parentheses

7n^2-8n=0

a = 7; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·7·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*7}=\frac{0}{14}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*7}=\frac{16}{14}
=1+1/7
$